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16 March, 15:24

How do you solve for c in this problem? 9 (c+5) + 3c=11

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Answers (2)
  1. 16 March, 18:33
    0
    Distribute the 9 to what it's multiplying in the parentheses

    9c+45+3c=11

    combine like terms of 3c and 9c

    12c+45=11

    get the variable by itself on one side by subtracting the constant

    12c=-34

    divide by 12

    c=-34/12
  2. 16 March, 19:24
    0
    1. First distribute the 9 (c+5) to get: 9c+45+3c=11

    2. The next thing to do is combine like terms to make the equation: 12c+45=11

    3. Now you should subtract 45 from 11 to get "c" by itself: 12c = - 34

    4. Divide - 34 by 12 to finalize your answer and get: c = - 34/12

    5. Finally simplify the fraction to get your final answer: c = - 17/6

    Final Answer: c = - 17/6
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