What is the smallest 3 consecutive positive integers if the product of the smallest and largest is 21 more than 9 times the middle number?

Lets say those positive consecutive integers are x, x+1, x+2 smallest to biggest respectively.

product of smallest and largest integer x (x+2) = 9 * (x+1) + 21

x^2+2x=9x+9+21

x^2-7x-30=0

x^2-10x+3x-30=0

x (x-10) + 3 (x-10)

x = - 3, x=10

we will take only positive part

so x=10

other consecutive integers would be 11,12

so answer is 10,11,12