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9 September, 14:54

Solve the double integral of e^y/x dy dx with outer limits as 0 and 2 and inner limits as 0 and x^2.

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  1. 9 September, 15:21
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    lets say integrand is e^ (y/x):

    ∫ (x = 0 to 1) ∫ (y

    = 0 to x^2) e^ (y/x) dy dx

    = ∫ (x = 0 to 1) xe^ (y/x)

    = ∫ (x = 0 to 1) x (e^x - 1) dx

    = ∫ (x = 0 to 1) (xe^x - x) dx

    = (xe^x - e^x) - (1/2) x^2

    = 1/2.
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