Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number. (Hint: You can use variables to represent the digits of a number. If a two-digit number has the digit x in tens place and y in one's place, the number will be 10x + y. Reversing the order of the digits will change their place value and the reversed number will 10y + x.) The difference of the original two-digit number and the number with reversed digits is

Question

Mathematics

Amanda

23 March, 03:05

Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number. (Hint: You can use variables to represent the digits of a number. If a two-digit number has the digit x in tens place and y in one's place, the number will be 10x + y. Reversing the order of the digits will change their place value and the reversed number will 10y + x.) The difference of the original two-digit number and the number with reversed digits is

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India Townsend · Answer 1

Let xy be this number:

5 (x+y) = (10x+y) - 13==> - 5x + 4y = - 132

& 4 (y+x) = 4 (10y+x) - 21==> 3x-6y = - 21

Slove this equation & you will get x=9 & y=8

Pitts · Answer 2

The anwser would be 27 because when done reversed it gives u the start off numbers