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3 July, 22:30

A population of 500 animals that decreases at an annual rate of 17%

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Answers (2)
  1. 4 July, 00:25
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    Answer : 0.17

    Have a wonderful day!
  2. 4 July, 02:02
    0
    This is exponential decay of the form:

    f=ir^t, f=final amount, i=initial amount, r=rate, t=time in this case:

    p (t) = 500 ((100-17) / 100) ^t

    p (t) = 500 (0.83) ^t
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