What is the product of (2p + 7) (3p2 + 4p - 3) ?

A=6p3 + 29p2 - 34p + 21

B=6p3 + 29p2 - 22p + 21

C=6p3 + 29p2 + 22p - 21

D=6p3 + 29p2 + 34p - 21

The answer is C=6p3 + 29p2 + 22p - 21

To calculate the product, we need to multiply each member of each multiplier:

(2p + 7) (3p2 + 4p - 3) = 2p · 3p² + 2p · 4p + 2p · - 3 + 7 ·3p² + 7 · 4p + 7 · - 3

= 6p³ + 8p² - 6p + 21p² + 28p - 21

= 6p³ + 8p² + 21p² + 28p - 6p - 21

= 6p³ + 29p² + 22p - 21

Therefore, the product of (2p + 7) (3p2 + 4p - 3) is 6p³ + 29p² + 22p - 21