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13 November, 18:17

Solve the following equations 2a+3=13 4b-2=22 5c+6=41 3d+4=16 7e-3=25 4f+7=15 9g-3=6 10h+4=44 16+2j=20 13-3k=10

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  1. 13 November, 20:04
    0
    1st bit is original question, italics is each stage and bold is final answer

    2a+3=13 2a=10a=5

    4b-2=22 4b=24b=6

    5c+6=41 5c=35c=7

    3d+4=16 3d=12d=4

    7e-3=25 7e=28e=4

    4f+7=15 4f=8f=2

    9g-3=6 9g=9g=1

    10h+4=44 10h=40h=4

    16+2j=20 2j=4j=2

    13-3k=10 13=10+3k 3=3kk=1
  2. 13 November, 21:29
    0
    1. a=5; 2. b=6; 3. c=7; 4. d=4; 5. e=4; 6. f=2; 7. g=1; 8. h=4; 9. j=2; 10. k=1.
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