What is the solution to the compound inequality 5x + 7 > - 8 and 3x + 7 ≤ 19?

x ≤ - 3 and x ≥ 4

-3 ≤ x < 4

x > - 3 and x ≥ 4

-3 < x ≤ 4

Solve each

5x+7>-8

minus 7 both sides

5x>-15

divide by 5

x>-3

3x+7≤19

minus 7 both sides

3x≤12

divide by 3

x≤4

so we got

x>-3 AND x≤4

and means that the solution set must satisfy both at once

so x is bigger than - 3 and less than or equal to 4

so between - 3 and 4 including 4

-3
last one