Solve the system by substitution:

y=2x+2

y=3x

a.) (3,9) b.) (1,4)

c.) (-2,-4)

So since we already have one of the unknowns equaling something, we start by substituting ...

y = 3x so let's substitute 3x into the first equation where the y is ...

y = 2x + 2

3x = 2x + 2

subtract 2x from each side

x = 2

So now we know x = 2 So we can now substitute it back into the equation but for x this time ...

y = 2x + 2

y = 2 (2) + 2

y = 4 + 2 = 6

So our solution set is

(2, 6)

You can check it by substituting x and y into both of the equations to see if you have a true statement ...

y = 2x + 2

6 = 2*2 + 2

6 = 6

y = 3x

6 = 3*2

6 = 6

Both true so it checks!

*note - I noticed that my solution was not one of your options, but if you substitute the available option that you gave into the equations none of them work, so take a look at your possible answers and see if you didn't leave something out.; )