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28 August, 11:52

A man is five times as old as his son. Four years ago, he was nine times as old. Find their present ages.

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  1. 28 August, 12:08
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    Let us assume the age of the son now = x

    Then

    The age of the man now = 5x

    Now we have to calculate the age of the son and father 9 years ago

    Age of the son 4 years ago = x - 4

    Age of the man 4 years ago = 5x - 4

    Then

    5x - 4 = 9 (x - 4)

    5x - 4 = 9x - 36

    5x - 9x = - 36 + 4

    - 4x = - 32

    MUltiplying both sides of the equation by - 1 we get

    4x = 32

    x = 32/4

    = 8

    So the present age of the son is 8 years

    Present age of the man = 5x

    = 5 * 8

    = 40 years

    So the present age of the man is 40 years and the present age of the son is 8 years.
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