What are the x intercepts of x^2-6x+5

Y = x² - 6x + 5

0 = x² - 6x + 5

x = - (-6) + / - √ ((-6) ² - 4 (1) (5))

2 (1)

x = 6 + / - √ (36 - 20)

2

x = 6 + / - √ (16)

2

x = 6 + / - 4

2

x = 3 + 2

x = 3 + 2 x = 3 - 2

x = 5 x = 1

y = x² - 6x + 5

y = (5) ² - 6 (5) + 5

y = 25 - 30 + 5

y = - 5 + 5

y = 0

(x, y) = (5, 0)

or

y = x² - 6x + 5

y = (1) ² - 6 (1) + 5

y = 1 - 6 + 5

y = - 5 + 5

y = 0

(x, y) = (1, 0)

The x-intercept of the problem is equal to 5 or 1.