Ask Question
12 March, 05:46

Factor completely - 7x2 + 14x - 21.

+5
Answers (2)
  1. 12 March, 08:57
    0
    Complete the square:

    -7x^2+14x-21=0 move constant to other side, add 21 to both sides

    -7x^2+14x=21 make the coefficient of x^2=1, divide both sides by - 7

    x^2-2x=-3 halve the linear coefficient, square it, add it to both sides, + 1

    x^2-2x+1=-2 now the left side is a perfect square

    (x-1) ^2=-2 take the square root of both sides

    x-1=±√-2 add 1 to both sides

    x=1±√-2 note that there are not real roots here because there is no real square root of a negative number ...

    x=1+i√2 and 1-i√2 so

    (x+1+i√2) (x+1-i√2)
  2. 12 March, 09:37
    0
    We can take out 7 because all of the terms include it:

    7 (-x^2+2x-3)

    Take out negative 1:

    -7 (x^2-2x+3)

    We cannot factor any further so the final answer is:

    -7 (x^2-2x+3)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Factor completely - 7x2 + 14x - 21. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers