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15 August, 14:49

A force (F) applied to an object of mass m1 produces an acceleration of 3.00 m/s^2.

The same force applied to a second object of mass m2 produces an acceleration of 1.00 m/s^2.

a) what is the value of the ratio m1/m2?

b) if m1 and m2 are combined into one object, what is its acceleration under the action of the force

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Answers (2)
  1. 15 August, 17:02
    0
    A) using f=ma, F=m1 x 3.00 = 3m1

    also F=m2 x 1.00 = m2

    as the Fs are the same: 3m1=m2

    this means that the ratio of m1 to m2 is 3 to 1 as there are 3 m1s for every m2.

    b) again using f=ma, the combination of the masses is m1 + m2 or 4m1 as there are 3m1s in m2. so F=4m1 x a = 3m1 (as F is the same for all of them).

    a = 3m1/4m1 = 3/4ms^-2
  2. 15 August, 17:49
    0
    A) For object with mass m1,

    F = m1 * 3

    m1 = F/3

    For object with mass m2,

    F = m2 * 1

    m2 = F

    Ratio of m1/m2

    (F/3) / F = 1/3
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