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30 January, 04:33

Prove:

lim x^3 = 8.

x approaches 2

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  1. 30 January, 08:27
    0
    When we compute the value of a limit, all that we do is to change the value of the parameter

    lim x^3 = (2) ^3 = 2x2x2=8

    x approaches 2
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