The area of the region under the curve of the function f (x) = 5x + 7 on the interval [1, b] is 88 square units, where b > 1.

What is the value of b?

We are given the area of the region under the curve of the function f (x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1

We need to find the integral of the function f (x) = 5x + 7 with the limits 1 and b

5/2 x^2 + 7x (limits: 1, b)

substitute the limits:

5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0

solve for b

Then after solving for b, this would be your interval input with 1: [1, b].