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2 January, 03:47

How do you solve for the standard form of y=2/3x-5?

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  1. 2 January, 06:43
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    Multiply by 3 to get rid of the fraction:

    3y=2x+15

    Move the x's to the left. Don't forget the sign change:

    -2x+3y=15

    Now reverse all signs to make the x part positive:

    2x-3y=-15
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