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15 July, 10:31

Solve the equation algebraically.

e^ (.05t) = 3 ... ?

+5
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  1. 15 July, 13:25
    0
    T = (ln (3)) /.5

    ln (e^.05t) = ln (3) 0.05t=ln (3) t=ln (3) / (0.05)
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