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30 August, 02:25

You throw a ball upward. its height h in feet after t seconds can be modeled by the function h=-16t^2+30t+6. after how many seconds will it hit the ground

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  1. 30 August, 04:10
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    When the ball hit the ground, the height will be equal to "0".

    h=0

    Then:

    -16t²+30t+6=0

    we have to solve this square equation:

    t=[-30⁺₋√ (900+384) ] / (-32)

    t = (-30⁺₋√1284) / (-32)

    we have two solutions:

    t₁ = (-30-√1284) / (-32) = 2.06

    t₂ = (-30+√1284) / (-32) = - 0.18 This solution is not valid.

    Answer: 2.06 seconds.

    t
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