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2 November, 07:05

How much would a 10th dog have to weight for the average weight in part (a) to be 250 pounds? Explain how you determined your answer.

95, 16, 5, 55, 23, 55 6, 8 53

average i got 35.11

i think the formula is (316+x) 10 = 250

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  1. 2 November, 07:48
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    (316 + x) / 10 = 250

    First: Multiply both sides by 10 to begin your isolation of x.

    250 * 10 = 2500

    Second: Subtract 316 from each side.

    2500 - 316 = 2184 lbs.
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