What is the value of the discriminant in the equation shown below?

x^2+3x-6=0

... ?

Question

Mathematics

Jeffrey Reid

19 December, 01:33

What is the value of the discriminant in the equation shown below?

x^2+3x-6=0

... ?

+2

Answers (2)

Know the Answer?

Nancy · Answer 1

Discriminant = b^2 - 4ac

a = 1

b = 3

c = - 6

3^2 - 4 (1x-6)

9 - (4 x - 6)

9 - - 24 = 33

Therefore it has 2 real roots

Oliver Robertson · Answer 2

Given:ax^2+bx+c=0The discriminant is:b^2-4 (a) (c) so it would be 33x^2-4 (1) (6)

3^2 - 4 (1) (-6)

[a] x^2 [+b] x [+c] = 0[1] x^2 [+3] x [-6] = 09 - 4 (1) (-6) = 9 - (-24)

=33

What is the value of the discriminant in the equation shown below?x^2+3x-6=0... ?

What is the value of the discriminant in the equation shown below?

x^2+3x-6=0

... ?