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31 May, 07:09

What is the solution to the following bernoulli de?

/[t^2 dy/dx+y^2=ty/]

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  1. 31 May, 07:30
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    So, from your equation t^2 dy/dx+y^2=ty

    Dividing boths side by t^2 we get

    dy/dx+y^2/t^2=y/t

    After re arranging

    dy/dx-y/t=-y^2/t^2

    after substituting we get

    w=-y^-3
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