A bag of sweet and sour jelly beans has 22 jelly beans. if 8 of the jelly beans are sweet and 6 of the jelly beans are red, and 10 jelly beans are neither sweet or red, how many sweet red jelly beans are in the bag

Question

Mathematics

Madden Decker

22 August, 23:08

A bag of sweet and sour jelly beans has 22 jelly beans. if 8 of the jelly beans are sweet and 6 of the jelly beans are red, and 10 jelly beans are neither sweet or red, how many sweet red jelly beans are in the bag

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Answers (1)

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Myles Stephens · Answer 1

When you subtract 10 from 22, the difference would be 12. This means that there are 12 beans that are either sweet or red. Another statement was that, there are 8 sweet jelly beans and 6 red jelly beans. However, if you total everything, 8+6+10, the sum would be 24. That would be more than the total number of beans in the bag which is 22. So, this means that 2 of those beans are sweet jelly beans and they are already included in the count for either the 8 or 6 sweet and red jelly beans, respectively.

The answer would be 2 sweet red jelly beans.