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5 March, 03:35

For the function y = - 2+5sin (pi/12 (x-2)), what is the maximum value?

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  1. 5 March, 06:26
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    To get the function y = - 2+5sin (pi/12 (x-2)), the maximum value can be determined by differentiating the function and equating it to zero. The value of x will give the maximum value of the function.

    dy/dx = 5 cos (pi/12 (x-2)) (pi/12)

    dy/dx = 5 pi/12 cos (pi/12 (x-2))

    Equate to zero:

    5 pi/12 cos (pi/12 (x-2)) = 0

    pi/12 (x-2) = 3pi/2

    x = 8

    Substituting,

    y = - 2 + 5sin (pi/12 (8-2)

    y = - 1.86
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