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9 October, 04:03

A diagram shows the part of graph y=ax^2 which is a parabola, it also gives me the coordinates (-3,45). How do i find the value of a?

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  1. 9 October, 07:36
    0
    You plug in the x and y coordinates 45=a3^2

    45=9a

    divide 9 on both sides

    a=5
  2. 9 October, 08:00
    0
    y = ax²

    45 = a (-3) ²

    45 = a (9)

    45 = 9a

    9 9

    5 = a
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