What is the approximate volume of a cone with a height of 11 ft and radius of 3 ft?

Use 3.14 to approximate pi, and round answers to two decimal places if necessary. Actually ttype in 3.14 don't use the symbol because it adds more numbers

___ft3

don't use this do 3.14

Substitute the values of the radius (r=3), the height (h=11), and an approximation of Pi (3.14) into the formula to find the volume of the cone.

V≈ + 1/3 ⋅3.14⋅ 3^2 ⋅11

Simplify.

Write 3.14 as a fraction with denominator 1.

V≈ + 1/3 ⋅ 3.14/1

Combine 1/3 and 3.14/1 to get 3.14/3.

V≈ + 3.14/3

Replace back in to larger expression.

V≈ + 3.14/3 ⋅ 3^2 ⋅11

Divide 3.14 by 3 to get 1.04666667.

V≈+1.04666667⋅ 3^2 ⋅11

Raise 3 to the power of 2 to get 9.

V≈+1.04666667⋅9⋅11

Multiply 1.04666667 by 9 to get 9.42.

V≈+9.42⋅11

Multiply 9.42 by 11 to get 103.62.

V≈+103.62

Remove trailing zeros from 103.62.

V≈+103.62 f t^3

Volume:

V≈+103.62ft^3

So volue of a cone=1/3 times (area of base) times height

area of base=circle so

find area of base/circle

pi times r^2

3.14 times 3^2

3.14 times 9

28.26

1/3 times 28.26 times 11=103.62 cm^3