Write an equation of the line perpendicular to y=2/5x+3 and through (4,-4)

Y = 2/5x + 3. The slope here is 2/5. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal. we " flip " the slope and change the sign. So the perpendicular line will need a slope of - 5/2.

y = mx + b

slope (m) = - 5/2

(4,-4) ... x = 4 and y = - 4

now we sub and find b, the y int

-4 = - 5/2 (4) + b

-4 = - 10 + b

-4 + 10 = b

6 = b

so ur perpendicular line is : y = - 5/2x + 6