In accute triangle abc side a=10, side b=12 and angle a is 42. Find angle b to the nearest degree

A triangle has 3 sides and 3 angles. The triangle involve is an acute triangle. This means that the rest of the angles in the triangle is acute. Acute angles are angles with measurement blow 90 degrees. To solve this problem we use the Sin Law. The ratio of the side and sine of the angle apposite to the side is constant. 10/sin (42) = 12/sin (x). Solve for x.

The answer is 53.41 degrees.