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9 May, 09:42

What is the slope and y-intercept of the equation 3 (y - 2) + 6 (x + 1) - 2 = 0?

A.) slope = - 2, y-intercept = 2/3

B.) slope = 2, y-intercept = 2/3

C.) slope = - 2, y-intercept = - 2/3

D.) slope = 2, y-intercept = - 2/3

E.) slope = - 2, y-intercept = 3/2

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Answers (2)
  1. 9 May, 13:26
    0
    3 (y - 2) + 6 (x + 1) - 2 = 0

    3y - 6 + 6x + 6 - 2 = 0

    3y + 6x - 2 = 0

    3y = - 6x + 2

    y = - 2x + 2/3

    slope = - 2, y intercept = 2/3
  2. 9 May, 13:33
    0
    You can try to convert to y=mx+b form

    m=slope

    b=yint

    solve for y

    first distribute

    3y-6+6x+6-2=0

    3y+6x+6-6-2=0

    3y+6x-2=0

    add 2 to both sides

    3y+6x=2

    minus 6x both sides

    3y=-6x+2

    divide both sides by 3

    y=-2x+2/3

    y=mx+b

    slope is - 2 and yint is 2/3

    A is answer
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Home » Mathematics » What is the slope and y-intercept of the equation 3 (y - 2) + 6 (x + 1) - 2 = 0? A.) slope = - 2, y-intercept = 2/3 B.) slope = 2, y-intercept = 2/3 C.) slope = - 2, y-intercept = - 2/3 D.) slope = 2, y-intercept = - 2/3 E.
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