F (x) = - 1/4 (x-1) ^2 - 3

I dont understand how to figure this question out, i ned the vertex, axis of symmetry, and the zeros.

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Mathematics

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1 September, 10:49

F (x) = - 1/4 (x-1) ^2 - 3

I dont understand how to figure this question out, i ned the vertex, axis of symmetry, and the zeros.

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Answers (1)

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Leia Garrett · Answer 1

F (x) = - 1/4 (x - 1) ² - 3

f (x) = - 1/4 (x - 1) (x - 1) - 3

f (x) = - 1/4 (x² - x - x + 1) - 3

f (x) = - 1/4 (x² - 2x + 1) - 3

f (x) = - 1/4 (x²) + 1/4 (-2x) + 1/4 (1) - 3

f (x) = 1/4x² + 1/2x + 1/4 - 3

f (x) = 1/4x² + 1/2x - 2 3/4

F (x) = - 1/4 (x-1) ^2 - 3I dont understand how to figure this question out, i ned the vertex, axis of symmetry, and the zeros.

F (x) = - 1/4 (x-1) ^2 - 3

I dont understand how to figure this question out, i ned the vertex, axis of symmetry, and the zeros.