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28 June, 07:45

Solving simultaneous equations with a quadratic, y=2x+5 and y=x^2-x-5

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  1. 28 June, 11:36
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    Set equal to eachother:

    2x+5=x^2-x-5

    0=x^2 - 3x - 10

    0 = (x-5) (x+2)

    x = - 2, 5
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