Solve. 3x2 + 4x = - 5

using quadratic equation ... ?

3x^2 + 4x - 5 = 0

x = [-b ±√ (b^2 - 4ac) ]/2a

a = 3

b = 4

c = - 5

x = [-4 ±√ (16 + 60) ]/6

x = [-4 ±√76]/6

x = [-4 ±√ (2^2 * 19) ]/6

x = [-4 ±2√19]/6

x = [-2 ±√19]/3

x = [-2 + √19]/3

x = [-2 + 4.35]/3

x = 2.35/3

x = 0.78 (rounded to the nearest hundredth)

x = [-2 - ±√19]/3

x = [-2 - 4.35]/3

x = - 6.35/3

x = - 2.12 (rounded to the nearest hundredth)

∴ x = - 2.12, 0.78 (rounded to the nearest hundredth)