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31 December, 06:01

Find the solution for m such that:

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  1. 31 December, 09:33
    0
    Let's raise the exponent three on both sides of the equation.

    1/x^2 = (x^m) ^3

    1/x^2 = x^ (3m)

    1 = x^2. x^ (3m)

    1 = x^ (2+3m)

    X^ (2+3m) = 1

    For this to be true:

    2+3m = 0

    3m = - 2

    m = - 2/3
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