Ask Question
13 June, 16:28

Factor:

4tan^2x - (4) / (cotx) + sinx (cscx) ... ?

+1
Answers (1)
  1. 13 June, 19:42
    0
    4tan^ (2) x - ((4) / (cotx)) + sinxcscx

    Multiply - 1 by the (4) / (cotx) inside the parentheses.

    4tan^ (2) x - (4) / (cotx) + sinxcscx

    To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.

    4tan^ (2) x * (cotx) / (cotx) - (4) / (cotx) + sin ...

    Complete the multiplication to produce a denominator of cotx in each expression.

    (4tan^ (2) xcotx) / (cotx) - (4) / (cotx) + (cot ...

    Combine the numerators of all expressions that have common denominators.

    (4tan^ (2) xcotx-4+cotxsinxcscx) / (cotx)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Factor: 4tan^2x - (4) / (cotx) + sinx (cscx) ... ? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers