The equation y=9.56x + 495.35 represents the number of calories, y, consumed in one day based on a persons weight, x. Jill consumes 1850 calories daily. Jaxon weighs 120 pounds. Which is an accurate comparison?

A) Jill weighs about 20 lbs more than Jaxon

B) Jaxon weighs about 20 lbs more than Jill

C) Jill consumes about 20 more calories than Jaxon

D) Jaxon consumes about 20 more calories than Jill

Have to fill in the variables for the equation for each person so ...

Y = 9.56 (x) + 495.35

Y = Number of calories

X = Weight

Jill's equation would be ...

1850 = 9.56 (x) + 495.35

Jaxon's equation would be ...

Y = 9.56 (120) + 495.35

Now you need to solve each one for the missing information ...

We'll start with Jill ...

1850 = 9.56 (x) + 495.35

You subtract 495.35 from both sides.

1850 - 495.35 = 1,354.65

Then you divide to find X.

9.56 (x) = 1,354.65

1,354.65 / 9.56 = 141.69

Rounded up ... 141.7 is Jill's weight

Now Jaxon's calorie intake ...

Y = 9.56 (120) + 495.35

First multiply 9.56 by 120 so ...

9.56 ・120 = 1,147.2

Then add to find Y.

1,147.2 + 495.35 = 1,642.55

Rounded up ... Jaxon's Calorie intake is 1,642.6

Then compare information and see what answer choice matches ...

Jill weighs 141.7 and intakes 1850 calories

Jaxon weighs 120 and intakes 1,642.6 calories

So your answer would be ...

A) Jill weighs about 20 more lbs than Jaxon