Ask Question
3 July, 22:31

Given the size and mass of each of the solid cubes X and Y, how many

times is the density of cube X greater than the density of cube Y?

+4
Answers (1)
  1. 4 July, 00:58
    0
    Since

    density = mass/volume (which is just another word for size)

    density of cube X = (cube X's mass) / (cube X's volume)

    lets name " (cube X's mass) / (cube X's volume) " as "x"

    density of cube Y = (cube Y's mass) / (cube Y's volume)

    lets name " (cube Y's mass) / (cube Y's volume) " as "y"

    then to calculate how many times is the density of cube X to density of cube Y, then it will be x/y

    if calculating how many times greater, then it is (x-y) / y

    though the phrase "how many times greater" can also mean "how many times".
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Given the size and mass of each of the solid cubes X and Y, how many times is the density of cube X greater than the density of cube Y? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers