A party rental company has chairs and tables for rent. the total cost to rent 8 chairs and 4 tables is $53 the total cost to rent 3 chairs and 2 tables is $24 what is the cost to rent a chair and each table

In order to solve this problem, we will let be

c = chairs, t=tables and have the following equations

8c+4t=53

3c+2t=24

we can solve this system by multiplying the second equation with - 2 and add it to the first one

8c+4t=53

-6c-4t=-48

we add them and get

2c=5, therefore c=5/2=2.5, so to rent a chair you need to pay 2.50 dollars

now we will replace c with 2.50

3 * (2.50) + 2t=24

7.50+2t=24 subtract 7.50 from both sides

2t=24-7.50

2t=16.50

t=16.50/2=8.25 8.25 to rent a table

we want to verify our answer

8 (2.50) + 4 (8.25) = 20+33=53

correct!