Ask Question
22 August, 04:21

How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid?

+3
Answers (1)
  1. 22 August, 06:10
    0
    My teacher taught me a simple equation for these types of problems:

    (percent of solution * amount of solution) + (percent of solution * amount of solution) = (percent of solution * total amount of solution)

    in simple terms: %amount + %amount = %total amount

    We know don't know how much gallons of 60% solution we need so it will be represented as x. We dont know the total amount either so it would have to be both solutions added together so 50 + x. Now lets solve:

    (0.60) (x) + (0.24) (50) = (0.50) (50 + x) simplify / distribute

    0.6x + 12 = 25 + 0.5x get all xs on one side and numbers on other

    0.1x + 12 = 25

    0.1x = 13 divide both sides by 0.1 to find x

    x = 130

    You need 130 gallons of 60% solution.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers