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31 August, 12:51

What are the excluded values? x+3/y (z+5)

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Answers (2)
  1. 31 August, 16:06
    0
    You cannot divide by 0

    so solve

    y (z+5) = 0

    y=0 and z+5=0

    y=0 and z=-5

    excluded values are y=0 and z=-5
  2. 31 August, 16:49
    0
    the answer is the third option: y = 0; z = - 5
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