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Today, 07:46

Given cosθ=1/3, find sin (90-θ)

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  1. Today, 09:16
    0
    Cos θ=1/3

    cos θ=sen (90-θ)

    therfore:

    sen (90-θ) = 1/3

    To chek

    θ=arc cos 1/3=70.53º

    sin (90-θ) = sin (90º-70.53º) = sin 19.47≈0.3333≈1/3
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