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31 October, 04:56

If the value of sinx=0.42, what is cos x?

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  1. 31 October, 06:41
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    From the relation of

    sin (x) ^2 + cos (x) ^2 = 1

    (0.42) ^2 + cos (x) ^2 = 1

    cos (x) ^2 = 1 - (0.42) ^2

    cos (x) = √ (1 - (0.42) ^2)

    cos (x) = 0.9075
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