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6 June, 16:35

X^2+y^2+3x=0 Find the x and y intercepts

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  1. 6 June, 16:57
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    Hello,

    x=0==> y=0

    y=0==> x²+3x=0==>x (x+3) = 0==>x=0 or x=-3

    x²+y²+3x=0

    ==> (x²+2*3/2x+9/4) + y²=9/4

    ==> (x+3/2) ²+y² = (3/2) ²

    is the equation of the circle of center (-3/2,0) and radius 3/2 where the tangent to the circle at (0,0) is the axis 0y.
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