One root of f (x) = x^3-9x^2+26x-24 is x = 2. What are all the roots of the function? Use the Remainder Theorem. x = 2, x = 3, or x = 4 x = - 2, x = - 3, or x = - 4 x = 1, x = 2, x = 3, or x = 13 x = - 1, x = - 2, x = - 3, or x = - 13

A. x=2, x=3, or x=4 is the correct answer

Using the remainder theorem, x = 2 is one of the root of the function. the x - 2 is a factor of the given function. by factoring the given function:

f (x) = x^3 - 9x^2 + 26x - 24

f (x) = (x - 2) (x - 3) (x - 4)

so the roots of the function are:

x - 2 = 0

x = 2

x - 3 = 0

x = 3

x - 4 = 0

x = 4