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28 November, 17:27

Solve the system by substitution x+2y-5z=40, 4y-z=18, 3x-y+z=3 ... step by step this is algebra 2

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  1. 28 November, 18:08
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    Step 1 - Solve for z in 4y - z = 18

    z = 4y - 18

    Step 2 - Substitute z = 4y - 18 into x + 2y - 5z = 40

    x - 18y + 90 = 40

    Step 3 - Substitute z = 4y - 18 into 3x - y + z = 3

    3x + 3y - 18 = 3

    Step 4 - Solve for x in x - 18y + 90 = 40

    x = 18y - 50

    Step 5 - Substitute x = 18y - 50 into z = 4y - 18

    z = 4y - 18

    Step 6 - Substitute x = 18y - 50 into 3x + 3y - 18 = 3

    57y - 168 = 3

    Step 7 - Solve for y in 57y - 168 = 3

    y = 3

    Step 8 - Substitute y = 3 into z = 4y - 18

    z = - 6

    Final Answers-

    x = 4

    y = 3

    z = - 6
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