Solve the system by substitution x+2y-5z=40, 4y-z=18, 3x-y+z=3 ... step by step this is algebra 2

Step 1 - Solve for z in 4y - z = 18

z = 4y - 18

Step 2 - Substitute z = 4y - 18 into x + 2y - 5z = 40

x - 18y + 90 = 40

Step 3 - Substitute z = 4y - 18 into 3x - y + z = 3

3x + 3y - 18 = 3

Step 4 - Solve for x in x - 18y + 90 = 40

x = 18y - 50

Step 5 - Substitute x = 18y - 50 into z = 4y - 18

z = 4y - 18

Step 6 - Substitute x = 18y - 50 into 3x + 3y - 18 = 3

57y - 168 = 3

Step 7 - Solve for y in 57y - 168 = 3

y = 3

Step 8 - Substitute y = 3 into z = 4y - 18

z = - 6

Final Answers-

x = 4

y = 3

z = - 6