1. What are the solutions to the following system?

-2x^2+y=-5

y=-3x^2+5

A) (0,2)

B) (1,-2)

C) (sq. root of 2,-1) and ( - sq. root of 2,-1)

D) (sq. root of 5, - 10) and (-sq. root of 5,-10)

-2x²+y=-5 = = > y=2x²-5

y=-3x²+5 = = > y=-3x²+5

since y=y then 2x²-5 = - 3x²+5===> 5x²=10 x²=2 & x₁=√2 & x₂ = - √2

Plug √2 into x (of 2x²-5) = = >y = f (√2) = - 1 & y = f (-√2) = - 1

So the Solution (√2, - 1)

& If you plug √2 into x (-3x²+5) = > y = f (√2) = - 1

So in both cases x=√2 & y=-1