A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f (t), in feet, at different times, t, in seconds:

f (t) = - 16t2 + 32t + 90

The average rate of change of f (t) from t = 4 seconds to t = 6 seconds is : blank: feet per second.

Question

Mathematics

Julie Wallace

28 April, 10:50

A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f (t), in feet, at different times, t, in seconds:

f (t) = - 16t2 + 32t + 90

The average rate of change of f (t) from t = 4 seconds to t = 6 seconds is : blank: feet per second.

+3

Answers (1)

Know the Answer?

Triston Wiley · Answer 1

F (6) = - 16·6²+32·6+90 = - 576 + 192 + 90 = - 294

f (4) = - 16· 4³+32·4+90=-256+128+90 = - 38

The average rate of change: [f (t2) - f (t1) ] / t2-t1=

[-294 - (-38) ] / (6-4) = - 256 : 2 = - 128 feet/s