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24 June, 19:49

How do i find sin^-1 (cos (pi)) and answer in radians in terms of pi

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  1. 24 June, 21:05
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    We have to find sin^ (-1) (cos π).

    cos π = cos 180° = - 1

    sin^ (-1) ( - 1) = 270° = 3 π / 2

    Answer:

    sin ^

    sin^ (-1) (cos π) = 3 π / 2
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