Find a cubic function with the given zeros. You must show your work for credit.

-6, 5, - 2

A polynomial with roots/zeros at r1, r2, r3 has factors

(x-r1) (x-r2) (x-r3)

zeroes - 6,5,-2

(x - (-6)) (x-5) (x - (-2)) or

(x+6) (x-5) (x+2)

the function is f (x) = (x+6) (x+2) (x-5) or expanded f (x) = x^3+3x^2-28x-60

Given zeroes are:

x1 = - 6

x2 = 5

x3 = - 2

The general formula for cubic function that has zeroes is: (factor form)

(x-x1) * (x-x2) * (x-x3)

if we express our zeroes we get:

(x+6) * (x-5) * (x+2) = (x^2 - 5x + 6x - 30) (x+2) = (x^2 + x - 30) (x+2) =

x^3 + x^2 - 30x + 2x^2 + 2x - 60 = x^3 + 3x^2 - 32x - 60