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18 February, 17:15

Which expression is equivalent to sec2xcot2x?

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  1. 18 February, 17:54
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    The basic rule of cos is

    cos x = 1 / sec x

    so

    sec 2x = 1 / cos 2x

    cot 2x = 1 / tan 2x

    tan 2x = sin 2x / cos 2x

    so

    cot 2x = cos 2x / sin 2x

    therefore

    sec2x cot2x

    (1/cos2x) * (cos2x / sin2x)

    1 / sin 2x

    but sin 2x = 1 / cosec 2x

    so the answer is cosec 2x
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