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Today, 14:56

What is the zero for 2x2-7=4

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Answers (2)
  1. Today, 18:08
    0
    2x^2-7=4

    subtract 4 from both sdies

    2x^2-11=0

    therefor

    2x^2=11

    divide by 2

    x^2=5.5

    square root both sdies

    x=-2.345 or 2.345
  2. Today, 18:32
    0
    2x² - 7 = 4

    +7 + 7

    2x² = 11

    2 2

    x² = 5 1/2

    x = √5 1/2
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