Factor Completely: 2x2 - 18

Prime

2 (x2 - 9)

2 (x + 3) (x - 3)

2 (x + 3) (x + 3)

To factor the given function, find a term that is divisible by both terms. For this problem, the factor would be 2, since 2x^2 and - 18 are both divisible by 2.

2 (x^2 - 9)

You could further factor out x^2 - 9 because it is factorable by (x - 3) and (x + 3). Thus, it would be

2 (x - 3) (x+3)